GoaltenderInterference Posted September 16, 2008 Share Posted September 16, 2008 The first weekend in grade 8 my Socials teacher gave me 7 hours of homework Link to comment Share on other sites More sharing options...
ovie8 Posted September 16, 2008 Share Posted September 16, 2008 The first weekend in grade 8 my Socials teacher gave me 7 hours of homework Link to comment Share on other sites More sharing options...
binkybonks Posted September 16, 2008 Share Posted September 16, 2008 The first weekend in grade 8 my Socials teacher gave me 7 hours of homework Link to comment Share on other sites More sharing options...
iheartluongo Posted September 16, 2008 Share Posted September 16, 2008 The first weekend in grade 8 my Socials teacher gave me 7 hours of homework Link to comment Share on other sites More sharing options...
Chester Posted September 16, 2008 Share Posted September 16, 2008 When did I say it wasn't? Link to comment Share on other sites More sharing options...
250Integra Posted September 16, 2008 Share Posted September 16, 2008 can someone help me with this too? (im horrible at math) twelve couples attend a party at which four identical door-prizes are to be given out to four different individuals. How many ways can the prizes be given out if no couple is to go home with more than one prize? Link to comment Share on other sites More sharing options...
Chester Posted September 16, 2008 Share Posted September 16, 2008 The first weekend in grade 8 my Socials teacher gave me 7 hours of homework Link to comment Share on other sites More sharing options...
binkybonks Posted September 16, 2008 Share Posted September 16, 2008 Impossible. I'm in grade 11 and all of my 8 classes are academics. I haven't had to do more than an hour of homework/night. I didn't even get any homework today. Link to comment Share on other sites More sharing options...
iheartluongo Posted September 16, 2008 Share Posted September 16, 2008 Obviously you are not taking either Chem 12 Calculus AP Biology 12 All in the same day :'( Link to comment Share on other sites More sharing options...
Denrik Posted September 16, 2008 Share Posted September 16, 2008 Impossible. I'm in grade 11 and all of my 8 classes are academics. I haven't had to do more than an hour of homework/night. I didn't even get any homework today. Link to comment Share on other sites More sharing options...
Ca.NucK10 Posted September 16, 2008 Share Posted September 16, 2008 whoops mispost Link to comment Share on other sites More sharing options...
canuckster19 Posted September 16, 2008 Share Posted September 16, 2008 can someone help me with this too? (im horrible at math) twelve couples attend a party at which four identical door-prizes are to be given out to four different individuals. How many ways can the prizes be given out if no couple is to go home with more than one prize? Link to comment Share on other sites More sharing options...
Duodenum Posted September 16, 2008 Share Posted September 16, 2008 Obviously you are not taking either Chem 12 Calculus AP Biology 12 All in the same day :'( Link to comment Share on other sites More sharing options...
LUONGO LINDEN Posted September 16, 2008 Share Posted September 16, 2008 i hate homework Link to comment Share on other sites More sharing options...
Anësthesia Posted September 16, 2008 Share Posted September 16, 2008 Okay anybody here good at math? Link to comment Share on other sites More sharing options...
DGFX. Posted September 16, 2008 Share Posted September 16, 2008 Okay anybody here good at math? Link to comment Share on other sites More sharing options...
Roberto Luongo!!! Posted September 17, 2008 Share Posted September 17, 2008 i hate homework Link to comment Share on other sites More sharing options...
250Integra Posted September 17, 2008 Share Posted September 17, 2008 Well, we are choosing all possible combinations of 4 numbers out of 12. So first you take the largest four numbers... 12x11x10x9 and then divide it by 2 = there are 5940 ways you can choose four different couples. Now the tricky part... there are 4 unique prizes and 4 winners, well there are 16 different ways of giving 4 unique prizes to 4 different winners so multiply 5940 x 16 95040 There's an easy way to explain how this works... Lets assume that there are 4 people and you want to know how many combinations of two you can have... So there's 4-3-2-1, and we only want two people so we multiply the two largest numbers together... 4 x 3 = 12 and then divide that by 2 = 6 So there are 6 possible combinations of two numbers 1-2, 1-3, 1-4, 2-3, 2-4, 3-4. Of course if you want to find all combinations where the same numbers reversed doesn't count as the same pair, ie 1-4, 4-1 just don't divide by two. I'm not good at explaining things but i hope this helps. Link to comment Share on other sites More sharing options...
believe_in_blue Posted September 17, 2008 Share Posted September 17, 2008 Well, we are choosing all possible combinations of 4 numbers out of 12. So first you take the largest four numbers... 12x11x10x9 and then divide it by 2 = there are 5940 ways you can choose four different couples. Now the tricky part... there are 4 unique prizes and 4 winners, well there are 16 different ways of giving 4 unique prizes to 4 different winners so multiply 5940 x 16 95040 There's an easy way to explain how this works... Lets assume that there are 4 people and you want to know how many combinations of two you can have... So there's 4-3-2-1, and we only want two people so we multiply the two largest numbers together... 4 x 3 = 12 and then divide that by 2 = 6 So there are 6 possible combinations of two numbers 1-2, 1-3, 1-4, 2-3, 2-4, 3-4. Of course if you want to find all combinations where the same numbers reversed doesn't count as the same pair, ie 1-4, 4-1 just don't divide by two. I'm not good at explaining things but i hope this helps. Link to comment Share on other sites More sharing options...
Roberto Luongo!!! Posted September 17, 2008 Share Posted September 17, 2008 It would be funny if someone asked for help in gym. :D Link to comment Share on other sites More sharing options...
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