Cunuck Posted September 18, 2013 Share Posted September 18, 2013 Because if that shift wasn't there, it would be possible to obtain negative values. But by vertically shifting the function up by the same magnitude as the amplitude (0.5), we remove the negative numbers. Link to comment Share on other sites More sharing options...
D.Doughty Posted September 18, 2013 Share Posted September 18, 2013 Because if that shift wasn't there, it would be possible to obtain negative values. But by vertically shifting the function up by the same magnitude as the amplitude (0.5), we remove the negative numbers. OH OK. I've been wanting to know this the whole time. haha thanks! Link to comment Share on other sites More sharing options...
Cunuck Posted September 18, 2013 Share Posted September 18, 2013 OH OK. I've been wanting to know this the whole time. haha thanks! Haha no worries. Math 12? Link to comment Share on other sites More sharing options...
D.Doughty Posted September 18, 2013 Share Posted September 18, 2013 Haha no worries. Math 12? first year math LOL Link to comment Share on other sites More sharing options...
babych Posted September 18, 2013 Share Posted September 18, 2013 yup you are i understand why its 0.5 cos[π(t − 8)/6] but i dont understand why its 0.5 cos[π(t − 8)/6]+0.5. Why vertical shift by .5? Also, the vertical displacement for sine and cosine is always found by using (max + min)/2. It's the average value of the function. Link to comment Share on other sites More sharing options...
babych Posted September 18, 2013 Share Posted September 18, 2013 given that f (x)= square root [1+(lnx)^2] for x greater or equal to 1, find the inverse function how do you do this? x=root 1+ (lny)^2 x^2=1+(lny)^2 x^2-1=(lny)^2 root (x^2-1)=lny e^(root(x^2-1) = y what am i doing wrong? The bolded should be the correction. Link to comment Share on other sites More sharing options...
D.Doughty Posted September 25, 2013 Share Posted September 25, 2013 A block of mass m = 0.570 kg rests on top of a block of mass M = 2.30 kg. A string attached to the block of mass M is pulled so that its tension is T = 6.20 N at a 20o angle to the horizontal as shown. The blocks move together. The coefficient of static friction at the surface between the blocks is μs = 0.43; there is no friction at the surface between block M and the floor. The tension T is now increased - what is the maximum tension, Tmax, with which the string can be pulled such that the blocks continue to move together (i.e. that the block of mass m does not start to slide on top of the block of mass M) so i found Ff mewFN=(0.43)(9.8)(0.570 =2.4 then F=ma Ftx-2.4=(2.3+0.57)(2.03) Ftx=8.228M Ftx/cos20=tmax tmax=8.76N Is this right? Link to comment Share on other sites More sharing options...
Alex the Great Posted September 25, 2013 Share Posted September 25, 2013 APA format. Help a brotha out. Link to comment Share on other sites More sharing options...
LeanBeef Posted October 8, 2013 Share Posted October 8, 2013 Anyone here inolved with electrical engineering or knows anything about series parallel circuits? Link to comment Share on other sites More sharing options...
D.Doughty Posted October 8, 2013 Share Posted October 8, 2013 A 15.0 g bullet with a speed of v = 235 m/s is fired into a block of wood that is initially at rest on a frictionless surface. The block of wood is attached to a horizontal massless spring with a spring constant k = 195 N/m that is initially uncompressed. The other end of the spring is attached to a wall as shown in the figure below. The bullet becomes imbedded in the block of wood which then compresses the spring a distance of 28.0 cm before momentarily coming to a stop. 1) determine the mass of the block i know you use conservation of momentum to do this but how do you find final velocity which is needed to solve the problem? Link to comment Share on other sites More sharing options...
Peaches Posted October 12, 2013 Share Posted October 12, 2013 Figured this would be the right place to ask this: Does anyone know what day Dan Russell's birthday is? We need to do a biography on someone and need a birthdate but I can't find it. Probably shouldn't be this hard. Link to comment Share on other sites More sharing options...
key2thecup Posted November 7, 2013 Share Posted November 7, 2013 Amateur, need help, can someone help me with this: B=7.5 A=15.3 h=? h2 = a2 + b2 h2 = (15.3)2 + (7.5)2 h = √ (15.3)2 + (7.5)2 h = √ 234.09 + 56.25 h = 23.2 Okay, I'm super amateur, I'm guessing the square root of the h gets transferred into √.... how does this work? I don't know how it works so what I did was, 234.09+56.25=290.34 which has the square root of 17.03 (Wrong answer) +'s to anyone who can teach me in laymen terms lol Link to comment Share on other sites More sharing options...
marleau_12 Posted November 8, 2013 Share Posted November 8, 2013 What's the answer? Link to comment Share on other sites More sharing options...
key2thecup Posted November 8, 2013 Share Posted November 8, 2013 What's the answer? 23.2 Link to comment Share on other sites More sharing options...
c00kies Posted November 8, 2013 Share Posted November 8, 2013 APA format. Help a brotha out. I know this is late, but owlpurdue is great for this. I'm also getting quite familiar with it due to my psych research class. Link to comment Share on other sites More sharing options...
Danthecanucksfan Posted November 8, 2013 Share Posted November 8, 2013 Scrolling through all these math equations is starting to make my head hurt. Just checking out the thread, mostly math eh? I recognize some of the pre-calc questions, barely passed pre-calc 11 Link to comment Share on other sites More sharing options...
key2thecup Posted November 8, 2013 Share Posted November 8, 2013 Scrolling through all these math equations is starting to make my head hurt. Just checking out the thread, mostly math eh? I recognize some of the pre-calc questions, barely passed pre-calc 11 You think you can help me with mine? Link to comment Share on other sites More sharing options...
marleau_12 Posted November 8, 2013 Share Posted November 8, 2013 23.2 \Lol I got same as you Link to comment Share on other sites More sharing options...
key2thecup Posted November 8, 2013 Share Posted November 8, 2013 \Lol I got same as you 17.03? Link to comment Share on other sites More sharing options...
marleau_12 Posted November 8, 2013 Share Posted November 8, 2013 17.03? Yeahhhhh Link to comment Share on other sites More sharing options...
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