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#31 D.Doughty

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Posted 28 November 2012 - 06:22 PM

Has anybody done the DELF exam before?


yah, it depends what level your taking though
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#32 D.Doughty

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Posted 28 November 2012 - 06:24 PM

This question is killing me, A rock is released from the top of a 30 m-high cliff at the same time as a ball is thrown upwards from the base of the cliff at 20 m/s. How much time elapses before they collide?


1.5s
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#33 believe in blue forever

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Posted 28 November 2012 - 06:24 PM

yah, it depends what level your taking though


I did the A2 exam today.
Which level have u done?
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#34 D.Doughty

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Posted 28 November 2012 - 06:32 PM

I did the A2 exam today.
Which level have u done?


I finished DELF B2

Did you pass?
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#35 GodzillaDeuce

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Posted 28 November 2012 - 06:49 PM

Ah....GodzillaDeuce, your great explanation helped me in my math test today. Thank you very much !


n/p
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well I'm sorry that gd is soo perfect


#36 believe in blue forever

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Posted 28 November 2012 - 06:53 PM

I finished DELF B2

Did you pass?


Wow B2 that's impressive
I did the exam today and the lady there told me I will probably find out in 3 weeks.

Did u just do B2? Or did u do an A level then upgrade to B2?
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#37 Nathan MacKinnon

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Posted 28 November 2012 - 07:02 PM

Wow B2 that's impressive
I did the exam today and the lady there told me I will probably find out in 3 weeks.

Did u just do B2? Or did u do an A level then upgrade to B2?


What is the DELF exam about?
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#38 believe in blue forever

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Posted 28 November 2012 - 07:20 PM

What is the DELF exam about?


The Diplôme d'études en langue française (DELF) (English: Diploma in French Studies) is a certification of French-language abilities for non-native speakers of French conducted by the FRENCH EMBASSY, administered by the International Centre for French Studies (Centre international d'études pédagogiques, or CIEP) for France's Ministry of Education. It is composed of four independent diplomas corresponding to the first four levels of the Common European Framework of Reference for Languages. Above this level, the "Proficient User" divisions are certified by theDALF.


http://www.ciep.fr/e...fdalf/index.php
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#39 Nathan MacKinnon

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Posted 28 November 2012 - 07:23 PM

http://www.ciep.fr/e...fdalf/index.php


Wow, I could probably take that....

how old do you have to be?
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#40 believe in blue forever

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Posted 28 November 2012 - 07:28 PM

Wow, I could probably take that....

how old do you have to be?


I'm not sure but there probably is some limit because only grade 12 got to do it in Surrey as far as I know

Edited by believe in blue forever, 28 November 2012 - 07:30 PM.

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Luongo is blamed for a lot of things. I think he was blamed for the teachers strike, and the high gas prices in Vancouver. Alain Vigneault

#41 D.Doughty

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Posted 28 November 2012 - 07:32 PM

Wow, I could probably take that....

how old do you have to be?


I'm pretty sure you can do it whenever you want but they only offer the exam certain times of the year
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#42 D.Doughty

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Posted 28 November 2012 - 07:33 PM

Wow B2 that's impressive
I did the exam today and the lady there told me I will probably find out in 3 weeks.

Did u just do B2? Or did u do an A level then upgrade to B2?


I did A2 before I did B2. There's a major difference lol
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#43 believe in blue forever

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Posted 28 November 2012 - 07:37 PM

I did A2 before I did B2. There's a major difference lol


Yeah half of my class did B1 yesterday and they were saying their exam was super difficult where as those of us who went today thought it was pretty easy
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Luongo is blamed for a lot of things. I think he was blamed for the teachers strike, and the high gas prices in Vancouver. Alain Vigneault

#44 Peaches

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Posted 28 November 2012 - 07:42 PM

I can help in French if needed.
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#45 TACIC

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Posted 28 November 2012 - 07:56 PM

I can do French too, I have done it my whole life
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#46 KoreanHockeyFan

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Posted 29 November 2012 - 12:54 AM

First Year Calculus:

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I don't understand how they got to the f'(1) equation on the second part of the solution. Oh and on the first part of the solution, f'(x) is there because of implicit differentiation, correct?

Thanks again.

Edited by KoreanHockeyFan, 29 November 2012 - 12:56 AM.

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#47 GodzillaDeuce

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Posted 29 November 2012 - 10:45 AM

I don't understand how they got to the f'(1) equation on the second part of the solution. Oh and on the first part of the solution, f'(x) is there because of implicit differentiation, correct?

Thanks again.


the f'(1) equation comes directly from the first equation you are given for f'(x), with the substitution x=1

when d/dx was applied to both sides, that was using implicit differentiation. as a result, you differentiated [f(x)]2 which needed the chain rule
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well I'm sorry that gd is soo perfect


#48 Nathan MacKinnon

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Posted 29 November 2012 - 11:04 PM

Physics question - Electrostatics - is Brass a conductor or an insulator of charge?

Is plastic a conductor or an insulator of charge?
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#49 Peaches

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Posted 29 November 2012 - 11:06 PM

Is plastic a conductor or an insulator of charge?


I'm pretty sure it's an insulator.
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#50 SkeeterHansen

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Posted 29 November 2012 - 11:07 PM

I wonder what "Google search" thinks of this...
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/=S=/


#51 Peaches

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Posted 29 November 2012 - 11:13 PM

@Yapierre

I need an actual human to explain to me live



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#52 KoreanHockeyFan

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Posted 30 November 2012 - 12:21 AM

the f'(1) equation comes directly from the first equation you are given for f'(x), with the substitution x=1

when d/dx was applied to both sides, that was using implicit differentiation. as a result, you differentiated [f(x)]2 which needed the chain rule


Yeah I noticed that when I took a second look at it in the morning, doh! Thanks again though.
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#53 CCF4E

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Posted 30 November 2012 - 12:34 AM

Multivariable Calculus, chapter of triple integrals
Help please! :(
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Edited by CCF4E, 30 November 2012 - 12:35 AM.

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Ehrhoff isn't from europe....


#54 GodzillaDeuce

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Posted 30 November 2012 - 01:33 AM

Multivariable Calculus, chapter of triple integrals
Help please! :(
Posted Image


you have two spheres in space, a small one on top of a large one where they overlap slightly (the smaller one sinks into the larger). the volume of each sphere alone is easy, but the volume of the entire snowman is the sum of each sphere minus the volume that they overlap.

if you are using Cartesian coordinates, then what you want is to find the equation of the circle where the two spheres intersect (this is key). this will tell you the numbers for the bounds of integration in either x or y, and then the function that forms the bounds for the other variable. Once you have that, your bounds for z are easy, just integrate from the bottom of the "head" to the top of the "body".

you can also switch to spherical or cylindrical coordinates (infact cylindrical might be best, theta does a full rotation, r goes from zero to the circle where the spheres intersect and z goes from the bottom to the top as before).

Try that first, hopefully that's enough, but if you need the solution:

Spoiler

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well I'm sorry that gd is soo perfect


#55 Mainly Mattias

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Posted 30 November 2012 - 02:28 AM

GD, I'm amazed you are still retaining this knowledge. :blink:
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#56 GodzillaDeuce

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Posted 30 November 2012 - 02:41 AM

GD, I'm amazed you are still retaining this knowledge. :blink:


hahaha, I'm not senile yet
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well I'm sorry that gd is soo perfect


#57 EoH

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Posted 30 November 2012 - 02:56 AM

has anyone read cormac mccarthy's book, outer dark? if you have much appreciate :)
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#58 canucklax

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Posted 30 November 2012 - 10:25 PM

Can anyone give a good explanation on calculating limits?

example: lim x->2 (x^(1/2)-2)/(x-4)

Edited by canucklax, 30 November 2012 - 10:25 PM.

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#59 GodzillaDeuce

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Posted 01 December 2012 - 12:18 PM

Can anyone give a good explanation on calculating limits?


well sure, if you have about a month to talk about all of the different types of limits and the various different limit laws at your disposal. I'll say this, the most important type of limits in Calculus are difference quotients: limh->0 (f(x+h)-f(x))/h. The trick here is that you want to just be able to plug in the number zero for h, but doing so now would cause this function to become 0/0, which is undefined, so you must first do some simplification.

For example, lets find limh->0 (f(x+h)-f(x))/h for the function f(x)=x2:

limh->0 (f(x+h)-f(x))/h = limh->0 ((x+h)2-x2)/h

=limh->0 (x2+2xh+h2-x2)/h

=limh->0 (2xh+h2)/h

=limh->0 (2x+h)

=2x+0

=2x

What is happening here is that the original expression ((x+h)2-x2)/h is a function of h that is undefined precisely where we are interested at looking: h=0. We get around that by saying "well if h=/=0, then this function looks exactly like 2x+h, and for this function at h=0 we get the expression 2x"

example: lim x->2 (x^(1/2)-2)/(x-4)


This function however is defined and continuous at the point x=2, so in this case we just plug that number in:

limx->2 (sqrt(x)-2)/(x-4) = (sqrt(2)-2)/(2-4)

=(sqrt(2)-2)/(-2)

=1-1/sqrt(2)
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well I'm sorry that gd is soo perfect


#60 Mr. White

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Posted 01 December 2012 - 01:27 PM

I'm procrastinating my homework right now :lol:
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