13Sundin13 Posted September 26, 2008 Share Posted September 26, 2008 sorry to say but both of those were wrong, the question says just to simplify. I really appreciate your effort though. Link to comment Share on other sites More sharing options...
WiLBoY Posted September 26, 2008 Share Posted September 26, 2008 sorry to say but both of those were wrong, the question says just to simplify. I really appreciate your effort though. Link to comment Share on other sites More sharing options...
WiLBoY Posted September 26, 2008 Share Posted September 26, 2008 The only thing i can think of is (-3√3)(-4√5)(2√12) = ( 24√180) = (24√4*45) = (48√45) then it becomes (48√9*5) = 144√5 Link to comment Share on other sites More sharing options...
WiLBoY Posted September 26, 2008 Share Posted September 26, 2008 The second one is wrong because i didn't even finish it... Link to comment Share on other sites More sharing options...
13Sundin13 Posted September 26, 2008 Share Posted September 26, 2008 its gr 11 math, i took apps 11 last year, im in grade 12 now and i just never learned this stuff so im having real trouble. the answer for the first one was 144√5 and the second one was 7(y+4)/(y+7)(y-2) Link to comment Share on other sites More sharing options...
WiLBoY Posted September 26, 2008 Share Posted September 26, 2008 its gr 11 math, i took apps 11 last year, im in grade 12 now and i just never learned this stuff so im having real trouble. the answer for the first one was 144√5 and the second one was 7(y+4)/(y+7)(y-2) Link to comment Share on other sites More sharing options...
WiLBoY Posted September 26, 2008 Share Posted September 26, 2008 (-3√3)(-4√5)(2√12) = ( 24√180) = (24√4*45) = (48√45) and 3y/y^2 + 5y -14 + 4/y-2 = u need a common denominator 3y + (5y*y^2) + (-14*y^2) + (4*y^2)/y-2 = (3y(y-2)) + (5y^3(y-2)) + (-14y^2(y-2)) + (4y^2) = 3y^2 - 6y + 5y^4 -10 -14y^3 + 28y + 4y^2 U should be able to solve for Y easily, if u can't ask again... Link to comment Share on other sites More sharing options...
WiLBoY Posted September 26, 2008 Share Posted September 26, 2008 3y^2 - 6y + 5y^4 -10y^3 -14y^3 + 28y^2 + 4y^2 Link to comment Share on other sites More sharing options...
Broski Posted September 26, 2008 Share Posted September 26, 2008 If one endpoint is located at A(4,7) and the midpoint is located at (1,2), what are the co-ordinates of the other end point? EDIT: I think I got it, do you just use the midpoint formula to figure it out? 4 + x(#2) , 7 + y(#2) ----------------------------- = (1,2) 2 Is that the right way to set it up, and then figure it out? So the co-ordinates of the other end point would be (-2,-3) ... Am I right? Link to comment Share on other sites More sharing options...
Ca.NucK10 Posted September 26, 2008 Share Posted September 26, 2008 take the mid point and subtract from the other end side so 4,7 -1,2 ------ 3,5 1,2 -3,5 =-2, -3 yes you got it right Link to comment Share on other sites More sharing options...
Broski Posted September 26, 2008 Share Posted September 26, 2008 Thanks Link to comment Share on other sites More sharing options...
binkybonks Posted September 26, 2008 Share Posted September 26, 2008 Anyone read the short story called The Tell-Tale Heart? Link to comment Share on other sites More sharing options...
believe_in_blue Posted September 26, 2008 Share Posted September 26, 2008 Thank you very much for your previous help! I have two more problems that will pretty much sum up all that i need to know. If you can explain how to simplify these that would be GREAT!! (-3√3)(-4√5)(2√12) and 3y/y^2+5y-14 + 4/y-2 THANK YOU!! Link to comment Share on other sites More sharing options...
Captain Bhangra Da Posted September 26, 2008 Share Posted September 26, 2008 I have no school tomorrow Thought I throw that out there :D Link to comment Share on other sites More sharing options...
WiLBoY Posted September 26, 2008 Share Posted September 26, 2008 Me neither. I don't have Fridays Link to comment Share on other sites More sharing options...
GoaltenderInterference Posted September 26, 2008 Share Posted September 26, 2008 I have no school tomorrow Thought I throw that out there :D Link to comment Share on other sites More sharing options...
Captain Bhangra Da Posted September 26, 2008 Share Posted September 26, 2008 Im in highschool Link to comment Share on other sites More sharing options...
WiLBoY Posted September 26, 2008 Share Posted September 26, 2008 Im in highschool Link to comment Share on other sites More sharing options...
Captain Bhangra Da Posted September 26, 2008 Share Posted September 26, 2008 I'm in elementary Link to comment Share on other sites More sharing options...
Theone- Posted September 26, 2008 Share Posted September 26, 2008 Anyone read the short story called The Tell-Tale Heart? Link to comment Share on other sites More sharing options...
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