Jump to content
The Official Site of the Vancouver Canucks
Canucks Community

Stuck On Homework? **The Homework Thread v0.01** is here!


More-is-on

Recommended Posts

(-3√3)(-4√5)(2√12) = ( 24√180) = (24√4*45) = (48√45)

and

3y/y^2 + 5y -14 + 4/y-2 = u need a common denominator

3y + (5y*y^2) + (-14*y^2) + (4*y^2)/y-2 =

(3y(y-2)) + (5y^3(y-2)) + (-14y^2(y-2)) + (4y^2)

= 3y^2 - 6y + 5y^4 -10 -14y^3 + 28y + 4y^2

U should be able to solve for Y easily, if u can't ask again...

Link to comment
Share on other sites

If one endpoint is located at A(4,7) and the midpoint is located at (1,2), what are the co-ordinates of the other end point?

EDIT: I think I got it, do you just use the midpoint formula to figure it out?

4 + x(#2) , 7 + y(#2)

----------------------------- = (1,2)

2

Is that the right way to set it up, and then figure it out? So the co-ordinates of the other end point would be (-2,-3) ...

Am I right?

Link to comment
Share on other sites

Archived

This topic is now archived and is closed to further replies.

  • Recently Browsing   0 members

    • No registered users viewing this page.
×
×
  • Create New...