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1/x - 4 = 1/(x+2)

1/x - 1/(x+2) = 4

(x+2-x)/[x(x+2)] = 4

2 = 4x2 + 8x

4x2 + 8x - 2 = 0

2(2x2 + 4x -1) = 0

Stick 2x2 + 4x - 1 = 0 into Quadratic equation

I THINK that's right. It matches Wolfram Alpha.

EDIT: I think I screwed up a sign, but it's sort of right.

You are correct.

OP whenever you have a problem of this nature, try to get all the unknowns out of the denominator.

1/x - 4 = 1/(x+2)

(1/x-4)(x+2) = 1

USE FOIL on the left hand side of the equation

1+2/x-4x-8 = 1


There is only one term with x in the denominator so multiply by x and you will get the quadratic equation which goaltender interference posted.

Use the quadratic equation formula to solve given by:

x=[-b(+ or -) root(b^2-4ac)]/2a

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