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The Sedin's 6th Sense

Simplest Yet One of the Toughest Math Questions I've Seen

98 posts in this topic

Is this math? Or just some weird scheme to science us all to death!

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1/3 is 1/3.

2/3 is 2/3.

3/3 is 3/3 or 1/1 or 1.

1/3 is not .333. This is an estimate.

2/3 is not .666. This is an estimate.

3/3 is not .999. This is just stupid.

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Are you serious? This is stupid. The first two are already broken down to the lowest fraction where 3/3 isn't. Not to mention to get your 0.33333... you divide 1 by 3 if you divide 3 by 3 you get 1. Seriously, this is retarded.

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can we rename this "stupidest and one of the simplest math questions I've seen" 1/3 doesn't equal .333, .333 is as close as decimals can get to the real number, due to the limits of decimals apparently everyone thinks this is a big math conspiracy or something

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Well, lets look at it algebraically,

lets x be .9999999 repeating,

x=.99999, if we multiply both sides by 100, or whatever number you want, we get, 100x = 99.999999

Now that we have two equations, to solve, we subtract 100x=99.99999 by x=.999999

100x=99.999999

- 1x= .999999

We now get, 99x=99

So, x=1, which means 1= .9999999 as they both equal to x.

In conclusion, 3/3 can be 1 OR .9999 as they are the equal. .99999 is just a different notation of writing 1.

This applies to other numbers as well, 2.999=3, or 4.49999 = 4.5, etc.

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Well, lets look at it algebraically,

lets x be .9999999 repeating,

x=.99999, if we multiply both sides by 100, or whatever number you want, we get, 100x = 99.999999

Now that we have two equations, to solve, we subtract 100x=99.99999 by x=.999999

100x=99.999999

- 1x= .999999

We now get, 99x=99

So, x=1, which means 1= .9999999 as they both equal to x.

In conclusion, 3/3 can be 1 OR .9999 as they are the equal. .99999 is just a different notation of writing 1.

This applies to other numbers as well, 2.999=3, or 4.49999 = 4.5, etc.

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Well, lets look at it algebraically,

lets x be .9999999 repeating,

x=.99999, if we multiply both sides by 100, or whatever number you want, we get, 100x = 99.999999

Now that we have two equations, to solve, we subtract 100x=99.99999 by x=.999999

100x=99.999999

- 1x= .999999

We now get, 99x=99

So, x=1, which means 1= .9999999 as they both equal to x.

In conclusion, 3/3 can be 1 OR .9999 as they are the equal. .99999 is just a different notation of writing 1.

This applies to other numbers as well, 2.999=3, or 4.49999 = 4.5, etc.

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You are completely wrong in your math, you give x 2 different values to get your desired 2 different answers, nice job tricking the others on here calling you a math genius but your math doesn't work

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Well, this is actually proof that 1= 0.99999 (continued)

The easy way to look at it's proof is 1/3 + 2/3 =3/3

Which means .333 continued + .666 continued =.999 continued.

Which means .999 continued and 1 are the exact same thing

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He is calling x 1 or 0.99999, because that proves that 1 and 0.99999 and the same numbers.

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dues to the limitations of decimals, those fractions don't exactly equal .33 or .66,that is just as close as we can get

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yes, but that still doesn't change the fact that .999 continued is equal to 1

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:picard:

no you don't understand, .33 does not equal 1/3, its as close to the actual number as we can get, the same for 2/3s and .666. this is why .666 is usually rounded to .67

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