-Goose- Posted October 9, 2010 Share Posted October 9, 2010 I got it (This is the way our teacher showed us) f(x)=8x^2+8x+6 f(x)-6=8x^2+8x f(x)-6=8(x^2+x) f(x)-6=8(x^2+1x+1/4) ----- You half the middle term, and square it, as the other poster mentioned f(x)-4=8(x+1/2)^2 f(x)= 8(x+1/2)^2+4 Link to comment Share on other sites More sharing options...
screech_darville Posted October 9, 2010 Share Posted October 9, 2010 Hey guys, so I'm a first year Child and Youth Care student at Dougie Daycare anyways, I'm writing a report regarding the homeless youth problem in BC and I'm wondering if anyone has more information about the problem that I could use for my background section. I have checked google scholar and my library catolouge but I only found 2 articles. The more info given to me, the better. thanks Link to comment Share on other sites More sharing options...
KoreanHockeyFan Posted October 10, 2010 Share Posted October 10, 2010 I have to write an essay regarding the Treaty of Versailles about if it was fair or not. Anyone got any ideas on what to write about? Link to comment Share on other sites More sharing options...
henrikownsall Posted October 12, 2010 Share Posted October 12, 2010 How do i make the sides equal (k+1) / (k+2)! = 1 - 1/(k+2)! Link to comment Share on other sites More sharing options...
-Goose- Posted October 12, 2010 Share Posted October 12, 2010 How do i make the sides equal (k+1) / (k+2)! = 1 - 1/(k+2)! Link to comment Share on other sites More sharing options...
PowerIce Posted October 12, 2010 Share Posted October 12, 2010 If a 220 pound force is applied to a 64 inch straight bar that is pivoted 6 inches from the end, what lift force is exerted? It's helpful to draw a diagram to help solve. I need the equation to solve this question. Link to comment Share on other sites More sharing options...
-Goose- Posted October 12, 2010 Share Posted October 12, 2010 You got your help in latenight Link to comment Share on other sites More sharing options...
PowerIce Posted October 12, 2010 Share Posted October 12, 2010 You got your help in latenight Link to comment Share on other sites More sharing options...
-Goose- Posted October 12, 2010 Share Posted October 12, 2010 Just go by significant digits if you're unsure. In your case it would be .5ft Link to comment Share on other sites More sharing options...
MadMonk Posted October 12, 2010 Share Posted October 12, 2010 How do i make the sides equal (k+1) / (k+2)! = 1 - 1/(k+2)! Link to comment Share on other sites More sharing options...
GodzillaDeuce Posted October 12, 2010 Share Posted October 12, 2010 How do i make the sides equal (k+1) / (k+2)! = 1 - 1/(k+2)! Link to comment Share on other sites More sharing options...
PlanB Posted October 21, 2010 Share Posted October 21, 2010 A farmer who usually uses a balance scale to weigh his wheat was bringing his heaviest stone to the scale. The stone weighed 40 kg. As he is carries the stone it falls to the ground and breaks apart into four pieces. At first he is dismayed, but then he realises that if the pieces of stone weighed certain amounts he would only need to use these and not all the other stones to weigh between 1 kg and 40 kg. How much does each of the four stones weigh in order for the farmer to be able to weigh any amount between 1 and 40 kg? Link to comment Share on other sites More sharing options...
-Goose- Posted October 21, 2010 Share Posted October 21, 2010 1 3 9 27 Link to comment Share on other sites More sharing options...
PlanB Posted October 21, 2010 Share Posted October 21, 2010 1 3 9 27 Link to comment Share on other sites More sharing options...
-Goose- Posted October 21, 2010 Share Posted October 21, 2010 It goes without saying that one stone has to be 1. That's because this makes any combination of the other three, three times as powerful (by adding or removing one unit). The next number that is far enough away that you don't get overlap with 1 when subtracting 1 is 3. Then you can add or subtract any amount within 4. Since 1-4 are already covered, 5 (first uncovered) plus 4 (distance cover-able by stones weighing 1 and 3) gives you 9. Now, you see a pattern emerge. The next number will be 27, as you can see by: 2(1 + 3 + 9) + 1 = 27. The most spread out, and most bottom-heavy, distribution of stone is therefore powers of 3 starting with 1. Also.. it just so happens 40 is the sum of powers of 3 starting with 3^0. Link to comment Share on other sites More sharing options...
-Goose- Posted October 21, 2010 Share Posted October 21, 2010 Edit: nvm Link to comment Share on other sites More sharing options...
no vacancy Posted October 21, 2010 Share Posted October 21, 2010 It goes without saying that one stone has to be 1. That's because this makes any combination of the other three, three times as powerful (by adding or removing one unit). The next number that is far enough away that you don't get overlap with 1 when subtracting 1 is 3. Then you can add or subtract any amount within 4. Since 1-4 are already covered, 5 (first uncovered) plus 4 (distance cover-able by stones weighing 1 and 3) gives you 9. Now, you see a pattern emerge. The next number will be 27, as you can see by: 2(1 + 3 + 9) + 1 = 27. The most spread out, and most bottom-heavy, distribution of stone is therefore powers of 3 starting with 1. Also.. it just so happens 40 is the sum of powers of 3 starting with 3^0. Link to comment Share on other sites More sharing options...
MadMonk Posted October 21, 2010 Share Posted October 21, 2010 . Link to comment Share on other sites More sharing options...
MadMonk Posted October 21, 2010 Share Posted October 21, 2010 Nevermind.. Link to comment Share on other sites More sharing options...
MadMonk Posted October 21, 2010 Share Posted October 21, 2010 i'm confident that one could prove in general that all integers =< (3n -1)/2 can be constructed from sums and differences of the integers 30, 31, 32, .... 3p, where p=n-1 Link to comment Share on other sites More sharing options...
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